Kasus Kejahatan di
Kota Semarang
Seorang peneliti ingin mengetahui apakah ada
perbedaan rata-rata kasus kejahatan di empat kecamatan semarang selama 4 bulan
terakhir
Dengan α = 5 % apakah kesimpulannya ?
Hasil dari
perhitungan SPSS adalah sebagai berikut :
Oneway
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Notes
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Output Created
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11-Dec-2014
12:51:43
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Comments
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Input
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Data
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E:\HADI BRANTAS W\$ - HADI
S2\TUGAS HADI\SMESTER II\MATEMATIKA\MTK - 3\New folder\Perbedaan Kasus
Kejahatan.sav
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Active Dataset
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DataSet1
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Filter
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<none>
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Weight
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<none>
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Split File
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<none>
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N of Rows in Working Data File
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16
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Missing Value Handling
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Definition of Missing
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User-defined missing values
are treated as missing.
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Cases Used
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Statistics for each analysis
are based on cases with no missing data for any variable in the analysis.
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Syntax
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ONEWAY Kasus BY Wilayah
/STATISTICS HOMOGENEITY
/MISSING ANALYSIS
/POSTHOC=SCHEFFE BONFERRONI ALPHA(0.05).
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Resources
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Processor Time
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00:00:00.031
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Elapsed Time
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00:00:00.012
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Test of Homogeneity of Variances
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Kasus Kejahatan di Kec
Semarang
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Levene Statistic
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df1
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df2
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Sig.
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2.500
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3
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12
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.109
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ANOVA
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Kasus Kejahatan di Kec
Semarang
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Sum of Squares
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df
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Mean Square
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F
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Sig.
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Between Groups
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423.500
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3
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141.167
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17.554
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.000
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Within Groups
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96.500
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12
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8.042
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Total
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520.000
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15
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Multiple
Comparisons
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Dependent Variable:Kasus
Kejahatan di Kec Semarang
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(I) Wilayah di Kecamatan
Semarang
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(J) Wilayah di Kecamatan
Semarang
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Mean Difference
(I-J)
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Std. Error
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Sig.
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95% Confidence
Interval
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Lower Bound
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Upper Bound
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Scheffe
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Utara
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Selatan
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12.750*
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2.005
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.000
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6.26
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19.24
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Barat
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7.250*
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2.005
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.027
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.76
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13.74
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Timur
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1.000
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2.005
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.968
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-5.49
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7.49
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Selatan
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Utara
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-12.750*
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2.005
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.000
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-19.24
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-6.26
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Barat
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-5.500
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2.005
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.108
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-11.99
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.99
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Timur
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-11.750*
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2.005
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.001
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-18.24
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-5.26
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Barat
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Utara
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-7.250*
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2.005
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.027
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-13.74
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-.76
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Selatan
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5.500
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2.005
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.108
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-.99
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11.99
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Timur
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-6.250
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2.005
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.060
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-12.74
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.24
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Timur
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Utara
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-1.000
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2.005
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.968
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-7.49
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5.49
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Selatan
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11.750*
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2.005
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.001
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5.26
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18.24
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Barat
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6.250
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2.005
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.060
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-.24
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12.74
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Bonferroni
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Utara
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Selatan
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12.750*
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2.005
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.000
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6.43
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19.07
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Barat
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7.250*
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2.005
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.021
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.93
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13.57
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Timur
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1.000
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2.005
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1.000
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-5.32
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7.32
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Selatan
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Utara
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-12.750*
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2.005
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.000
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-19.07
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-6.43
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Barat
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-5.500
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2.005
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.107
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-11.82
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.82
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Timur
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-11.750*
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2.005
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.000
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-18.07
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-5.43
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Barat
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Utara
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-7.250*
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2.005
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.021
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-13.57
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-.93
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Selatan
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5.500
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2.005
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.107
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-.82
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11.82
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Timur
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-6.250
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2.005
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.053
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-12.57
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.07
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Timur
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Utara
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-1.000
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2.005
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1.000
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-7.32
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5.32
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Selatan
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11.750*
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2.005
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.000
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5.43
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18.07
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Barat
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6.250
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2.005
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.053
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-.07
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12.57
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*. The mean difference is
significant at the 0.05 level.
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Kasus Kejahatan di Kec Semarang
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Wilayah di
Kecamatan Semarang
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N
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Subset for alpha = 0.05
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1
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2
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3
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Scheffea
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Selatan
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4
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35.50
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Barat
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4
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41.00
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41.00
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Timur
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4
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47.25
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47.25
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Utara
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4
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48.25
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Sig.
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.108
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.060
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.968
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Means for groups
in homogeneous subsets are displayed.
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a. Uses Harmonic
Mean Sample Size = 4,000.
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Kriteria keputusan
didasarkan atas angka dibawah Sig (2-tailed) tersebut dengan pedoman sebagai
berikut :
Jika Sig >
0.05, maka Ho Diterima
Jika Sig <
0.05, maka Ho Ditolak
Perhatikan bahwa
dari output diatas dapat diambil kesimpulan bahwa Ho ditolak karena Sig (2-tailed)
= 0.000 sehingga Sig < 0.05.dan kesimpulannya adalah menolak kapasitas dari Ho
Hasil dari
perhitungan MS. Excel adalah sebagai berikut :
Diagram
Batang
.png)
Diagram Lingkaran
.png)
